Wave Mechanics Question 101
Question: The ratio of densities of nitrogen and oxygen is 14:16. The temperature at which the speed of sound in nitrogen will be same at that in oxygen at 55oC is
[EAMCET (Engg.) 1999]
Options:
A) 35°C
B) 48°C
C) 65°C
D) 14°C
Show Answer
Answer:
Correct Answer: D
Solution:
$ v=\sqrt{\frac{\gamma ,RT}{M}} $
Therefore $ \frac{T _{N}}{T _{0}}=\frac{M _{N}}{M _{0}} $
Therefore $ \frac{T _{N}}{273+55}=\frac{14}{16}=\frac{7}{8} $
Therefore $ T _{N}=287K=14{}^\circ C $
BETA
