Wave Mechanics Question 872

Question: The ratio of densities of nitrogen and oxygen is 14:16. The temperature at which the speed of sound in nitrogen will be same at that in oxygen at 55oC is

[EAMCET (Engg.) 1999]

Options:

A) 35°C

B) 48°C

C) 65°C

D) 14°C

Show Answer

Answer:

Correct Answer: D

Solution:

$ v=\sqrt{\frac{\gamma ,RT}{M}} $

Therefore $ \frac{T _{N}}{T _{0}}=\frac{M _{N}}{M _{0}} $

Therefore $ \frac{T _{N}}{273+55}=\frac{14}{16}=\frac{7}{8} $

Therefore $ T _{N}=287K=14{}^\circ C $



sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें