Wave Mechanics Question 892

Two tuning forks A and B vibrating simultaneously produce 5 beats. Frequency of B is 512. It is seen that if one arm of A is filed, then the number of beats increases. Frequency of A will be 517 Hz or 507 Hz

[MP PMT 1991]

Options:

502

507

517

522

Show Answer

Answer:

Correct Answer: C

Solution:

After filling frequency increases, so $ n _{A} $ decreases (¯). Also it is given that beat frequency increases (i.e., x ­) Hence nA¯ ? nB = x­ … (i) Correct nB ? nA­ = x­ … (ii) Wrong

Therefore nA = nB + x = 512 + 5 = 517 Hz.



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