Wave Mechanics Question 900
Question: Two tuning forks A and B give 4 beats per second. The frequency of A is 256 Hz. On loading B slightly, we get 5 beats in 2 seconds. The frequency of B after loading is
[Haryana CEE 1996]
Options:
A) 253.5 Hz
B) 258.5 Hz
C) 260 Hz
D) 252 Hz
Show Answer
Answer:
Correct Answer: C
Solution:
nA = Known frequency = 256 Hz, nB = ? x = 4 beats per sec which is decreasing (4 bps to ) after loading (i.e. x¯) Unknown tuning fork B, is loaded so nB¯ Hence nA ? nB¯ = x¯ … (i) Wrong nB¯ ? nA = x¯ … (ii) Correct
Therefore nB = nA + x = 256 + 4 = 260 Hz.
BETA
