Wave Mechanics Question 550
Question: The displacement of a particle in SHM is $ x=10\sin ( 2t-\frac{\pi }{6} ) $ metre. When its displacement is 6 m, the velocity of the particle (in m s~1) is
Options:
A) 8
B) 24
C) 16
D) 10
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Given, $ x=10\sin ,( 2t-\frac{\pi }{6} ) $
$ A=10,and,\omega =2Hz $
$ \
Therefore v=\omega \sqrt{A^{2}-d^{2}}=2\sqrt{{{(10)}^{2}}-{{(6)}^{2}}} $
$ 2\sqrt{100-36}=2\times 8=16m,{{s}^{-1}} $
BETA
