Wave Mechanics Question 553
Question: The displacement vs time of a particle executing SHM is shown in figure. The initial phase $ \phi $ is
Options:
A) $ -\pi <\phi <-\frac{\pi }{2} $
B) $ \pi <\phi <\frac{3\pi }{2} $
C) $ -\frac{3\pi }{2}<\phi <-\pi $
D) $ \frac{\pi }{2}<\phi <\pi $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] For $ x=(-A), $ we have $ -A=A\sin ,(\omega \times 0+{\phi _{0}}),or,{\phi _{0}}=-\frac{\pi }{2} $ . So for $ x<(-A),,{\phi _{0}}<(-\pi /2) $ .
BETA
