Wave Mechanics Question 562
Question: A body executes simple harmonic motion. The potential energy (P.E.), the kinetic energy (K.E.) and total energy (T.E.) are measured as a function of displacement x. Which of the following statement is true?
Options:
A) P.E. is maximum when x = 0.
B) K.E. is maximum when x = 0.
C) T. E. is zero when x = 0.
D) K.E. is maximum when x is maximum.
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ K=\frac{1}{2}m{{\omega }^{2}}(A^{2}-x^{2}),\
Therefore ,{K _{\max }}=\frac{1}{2}m{{\omega }^{2}}A^{2}, $ at $ x=0 $
BETA
