Wave Mechanics Question 570
Question: The angular velocity and the amplitude of a simple pendulum is o and a respectively. At a displacement x from the mean position if its kinetic energy is T and potential energy is V, then the ratio of T to Vis
Options:
A) $ \frac{(a^{2}-x^{2}{{\omega }^{2}})}{x^{2}{{\omega }^{2}}} $
B) $ \frac{x^{2}{{\omega }^{2}}}{(a^{2}-x^{2}{{\omega }^{2}})} $
C) $ \frac{(a^{2}-x^{2})}{x^{2}} $
D) $ \frac{x^{2}}{(a^{2}-x^{2})} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ P.E.,,V=\frac{1}{2}m{{\omega }^{2}}x^{2} $ and $ K.E.,T=\frac{1}{2}m{{\omega }^{2}}(a^{2}-x^{2}) $
$ \
Therefore \frac{T}{V}=\frac{a^{2}-x^{2}}{x^{2}} $
BETA
