Wave Mechanics Question 573
Question: A simple harmonic motion has an amplitude A and time period T. The time required by it to travel from x=A to x=A/2 is
Options:
A) T/6
B) T/4
C) T/3
D) T/2
Show Answer
Answer:
Correct Answer: A
Solution:
[a] At extreme position $ y=A,\sin (\omega t+\frac{\pi }{2})=A\cos ,\omega t $ Now $ y=A/2,then,A/2=A,\cos ,\omega t $
$ \Rightarrow \omega t={{\cos }^{-1}}(1/2), $
$ \frac{2\pi }{T}t=\frac{\pi }{3}\Rightarrow t=T/6 $
BETA
