Wave Mechanics Question 581
Question: What will be the force constant of the spring system shown in figure?
Options:
A) $ \frac{k _{1}}{2}+k _{2} $
B) $ {{[ \frac{1}{2k _{1}}+\frac{1}{k _{2}} ]}^{-1}} $
C) $ [ \frac{1}{2k _{1}}+\frac{1}{k _{2}} ] $
D) $ {{[ \frac{2}{k _{1}}+\frac{1}{k _{2}} ]}^{-1}} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Two springs of force constants $ k _{1} $ and $ k _{1} $ are in parallel. Hence $ k’=k _{1}+k _{1}=2k _{1} $ The third spring $ k _{2} $ is in series with spring of force constant $ k’ $ .
$ \
Therefore ,\frac{1}{k}=[ \frac{1}{2k _{1}}+\frac{1}{k _{2}} ]ork={{[ \frac{1}{2k _{1}}+\frac{1}{k _{2}} ]}^{-1}} $
BETA
