Wave Mechanics Question 585
Question: A block rests on a horizontal table which is executing SHM in the horizontal plane with an amplitude ‘a’. If the coefficient of friction is $ ‘\mu ’ $ , then the block just starts to slip when the frequency of oscillation is
Options:
A) $ \frac{1}{2\pi }\sqrt{\frac{\mu g}{a}} $
B) $ \sqrt{\frac{\mu g}{a}} $
C) $ 2\pi \sqrt{\frac{a}{\mu g}} $
D) $ \sqrt{\frac{a}{\mu g}} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] For the block is about to slip, $ \mu g={{\omega }^{2}}a $
$ \omega =\sqrt{\frac{\mu g}{a}}\Rightarrow v=\frac{1}{2\pi }\sqrt{\frac{\mu g}{a}} $
BETA
