Work Energy And Power Question 299
Question: A shell is fired from a cannon with a velocity v (m/sec.) at an angle 9 with the horizontal direction. At the highest point in its path it explodes into two pieces of equal mass. One of the pieces retraces its path to the cannon and the speed (in m/sec.) of the other piece immediately after the explosion is
Options:
A) $ 3vcos\theta $
B) $ 2vcos\theta $
C) $ \frac{3}{2}vcos\theta $
D) $ \sqrt{\frac{3}{2}}vcos\theta $
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Answer:
Correct Answer: A
Solution:
[a] As one piece retraces its path, the speed of this piece just after explosion should be $ vcos\theta $ (At highest point just after explosion) Applying conservation of linear momentum at the highest point; $ m( v\cos \theta )=\frac{m}{2}\times v’-\frac{m}{2}\times v\cos \theta $
$ 3v\cos \theta =v’ $
BETA
