Work Energy And Power Question 201
From an automatic gun a man fires 360 bullets per minute with a speed of 360 m/s. If each weighs 20 g, the power of the gun is [Pb. PET 2003]
Options:
A) $ 600W $
B) $ 300W $
C) $ 150W $
D) $ 75W $
Show Answer
Answer:
Correct Answer: A
Solution:
Power of gun $ =\frac{\text{Total K}\text{.E}\text{. of fired bullet}}{\text{time}} $
$ =\frac{n\times \frac{1}{2}mv^{2}}{t}=\frac{360}{60}\times \frac{1}{2}\times 2\times {10^{-2}}\times {{(100)}^{2}}=600W $
BETA
