Work Energy And Power Question 59
Question: If a lighter body (mass $ M_1 $ and velocity $ V_1 $ ) and a heavier body (mass $ M_2 $ and velocity $ V_2 $ ) have the same kinetic energy, then [MP PMT 1997]
Options:
A) $ M_2V_2<M_1V_1 $
B) $ M_2V_2=M_1V_1 $
C) $ M_2V_1=M_1V_2 $
D) $ M_2V_2>M_1V_1 $
Show Answer
Answer:
Correct Answer: D
Solution:
$ P=\sqrt{2mE}. $ If kinetic energy are equal then
$ P\propto \sqrt{m} $ i.e., heavier body posses large momentum .
As $ M_1<M_2 $ therefore $ M_1V_1<M_2V_2 $
BETA
