Work Energy And Power Question 61
Question: A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, the work required to pull the hanging part on to the table is [IIT 1985; MNR 1990; AIEEE 2002; MP PMT 1994, 97, 2000; JIPMER 2000]
Options:
A) $ MgL $
B) $ MgL/3 $
C) $ MgL/9 $
D) $ MgL/18 $
Show Answer
Answer:
Correct Answer: D
Solution:
$ W=\frac{MgL}{2n^{2}}=\frac{MgL}{2{{(3)}^{2}}}=\frac{MgL}{18} $ (n = 3 given)
BETA
