Work Energy And Power Question 66
Question: If g is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of an object of mass m raised from the surface of earth to a height equal to the radius of the earth R, is [IIT 1983]
Options:
A) $ \frac{1}{2}mgR $
B) 2 mgR
C) mgR
D) $ \frac{1}{4}mgR $
Show Answer
Answer:
Correct Answer: A
Solution:
Gain in potential energy $ \Delta U=\frac{mgh}{1+\frac{h}{R}} $
If $ h=R $ then $ \Delta U=\frac{mgR}{1+\frac{R}{R}}=\frac{1}{2}mgR $
BETA
