Work Energy And Power Question 208
Question: Calculate the work done on the tool by $ \vec{F}( 11.25\hat{i}+11.25\hat{j} )N $ if the tool is first moved out along the x-axis to the point $ x=3.00m, $
$ y=0 $ and then moved parallel to the y-axis to $ x=3.00m, $
$ y=3.00m $ .
Options:
A) 67.5 J
B) 85 J
C) 102 J
D) 7.5 J
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Net displacement is $ ( 3 \hat{i}+3\hat{j} ) $
so work done $ = \vec{F}.\Delta \vec{s} = 11.25( \hat{i}+\hat{j} ).( 3 \hat{i}+ 3\hat{j} ) $
$ = 33.75 \times 2=67.50 J $
BETA
