Work Energy And Power Question 102
Question: A ball of weight 0.1 kg coming with speed 30 m/s strikes with a bat and returns in opposite direction with speed 40 m/s, then the impulse is (Taking final velocity as positive) [AFMC 1997]
Options:
A) $ -0.1\times (40)-0.1\times (30) $
B) $ 0.1\times (40)-0.1\times (-30) $
C) $ 0.1\times (40)+0.1\times (-30) $
D) $ 0.1\times (40)-0.1\times (20) $
Show Answer
Answer:
Correct Answer: B
Solution:
Impulse = change in momentum $ mv_2-mv_1 $ = $ 0.1\times 40-0.1\times (-30) $
BETA
