Work Energy And Power Question 175
Question: A body of mass 4 kg moving with velocity 12 m/s collides with another body of mass 6 kg at rest. If two bodies stick together after collision, then the loss of kinetic energy of system is [J&K CET 2005]
Options:
A) Zero
B) 288 J
C) 172.8 J
D) 144 J
Show Answer
Answer:
Correct Answer: C
Solution:
Loss in K.E. = $ \frac{m_1m_2}{2(m_1+m_2)}{{( u_1-u_2 )}^{2}} $ = $ \frac{4\times 6}{2\times 10}\times {{(12-0)}^{2}} $ = 172.8 J
BETA
