Work Energy And Power Question 229
Question: 300 J of work is done in sliding a 2 kg block up an inclined plane of height 10m. Taking $ g=10m/s^{2} $ , work done against friction is
Options:
A) 100J
B) zero
C) 1000J
D) 200J
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Work done against gravity $ =mgsin\theta \times d $
$ =2\times 10\times 10=200J ( dsin\theta =10 ) $
Actual work done = 300 J Work done against friction $ = 300 - 200 = 100 J $
BETA
