Work Energy And Power Question 248
Question: A man places a chain of mass m and length L on a table slowly. Initially the lower end of the chain just touches the table. The man drops the chain when half of the chain is in vertical position. Then work done by the man in this process is
Options:
A) $ -mg\frac{L}{2} $
B) $ -\frac{mgL}{4} $
C) $ -\frac{3mgL}{8} $
D) $ -\frac{mgL}{8} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] The work done by man is equal to the magnitude of the decreases in potential energy of chain $ \Delta U=mg\frac{L}{2}-\frac{m}{2}g\frac{L}{4}=3mg\frac{L}{8}\therefore W=\frac{3mgL}{8} $
BETA
