PYQ NEET- ৰাসায়নিক ভাৰসাম্য-1 L-1

=== ফ্ৰণ্ট মেটা ফিল্ডছ ===
title: PYQ NEET- কেমিকেল ইকুইলিব্ৰিয়াম-1 L-1

=== বডি ===

প্ৰশ্ন: $\mathrm{K}_{\mathrm{p}}$ নিম্নলিখিত প্ৰতিক্ৰিয়াৰ বাবে $1000 \mathrm{~K}$ ত $$#

\mathrm{CO}_2(\mathrm{~g})+\mathrm{C}(\mathrm{s}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}) $$ হৈ 3.0 হয়।

What will be the value of $\mathrm{K}_{\mathrm{c}}$ for the reaction at the same temperature?

(Given : $\mathrm{R}=0.083 \mathrm{~L}$ bar K $^{-1} \mathrm{~mol}^{-1}$ )

A) 3.6

B) 0.36

C) $3.6 \times 10^{-2}$

D) $3.6 \times 10^{-3}$

উত্তৰ: $3.6 \times 10^{-2}$#

সমাধান:#

$\begin{aligned} & \mathrm{CO}2(\mathrm{~g})+\mathrm{C}(\mathrm{s}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}) \ & \Delta \mathrm{n}{\mathrm{g}}=2-1=1 \ & \mathrm{~K}{\mathrm{p}}=\mathrm{K}{\mathrm{c}}(\mathrm{RT})^{\Delta \mathrm{n}{\mathrm{g}}} \ & \mathrm{K}{\mathrm{p}}=\mathrm{K}{\mathrm{c}}(\mathrm{RT}) \ & {\left[\because \mathrm{K}{\mathrm{p}}=3\right]} \ & \mathrm{K}{\mathrm{c}}=\frac{\mathrm{K}{\mathrm{p}}}{\mathrm{RT}}=\frac{3}{0.083 \times 1000} \ & =0.036 \ & =3.6 \times 10^{-2}\end{aligned}$