PYQ NEET- চিমিয়াল সমতা-1 ল-8

প্ৰশ্ন: গিবছ এনেচ $\Delta \mathrm{G}^0=+63.3 \mathrm{~kJ}$ ব্যৱহাৰ কৰি, নিম্নলিখিত প্ৰতিক্ৰিয়াৰ $\mathrm{Ag}2 \mathrm{CO}{3(\mathrm{~s})} \rightleftharpoons 2 \mathrm{Ag}^{+}{ }_{(\mathrm{aq})}+\mathrm{CO}3{ }^{2-}{ }{(\mathrm{aq})}$#

$\mathrm{K}_{\mathrm{sp}}$ $\mathrm{Ag}2 \mathrm{CO}{3(\mathrm{~s})}$ জলত $25^{\circ} \mathrm{C}$ ত $\left(\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)$

A) $3.2 \times 10^{-26}$

B) $8.0 \times 10^{-12}$

C) $2.9 \times 10^{-3}$

D) $7.9 \times 10^{-2}$

উত্তৰ: $8.0 \times 10^{-12}$#

সমাধান:#

আমি জানি, $\Delta \mathrm{G}^0=-2.303 \mathrm{RT} \log \mathrm{K}{\mathrm{sp}}$
$$ \begin{aligned} & \therefore 63300=-2.303 \times 8.314 \times 298 \log \mathrm{K}{\mathrm{sp}} \ & \Rightarrow \log \mathrm{K}{\mathrm{sp}}=-11.09 \ & \Rightarrow \mathrm{K}{\mathrm{sp}}=10^{-11.09} \ & =8.0 \times 10^{-12} \end{aligned} $$