Gausss Law In Electrostatics

Concepts: Electric field due to a point charge:

  • The electric field due to a point charge is given by the equation:

$$\overrightarrow{E}=\frac{1}{4\pi\epsilon_0}\frac{q}{r^2}\hat{r}$$ Where,

(\overrightarrow{E}) is the electric field vector.

(q) is the magnitude of the point charge.

(r) is the distance from the point charge to the observation location.

(\hat{r}) is the unit vector pointing from the point charge to the observation location.

Electric flux:

  • Electric flux is a measure of the amount of electric field passing through a given surface. It is given by the equation: $$\Phi_E=\oint\overrightarrow{E}\cdot\hat{n}dA$$ Where (\Phi_E) is the electric flux (\overrightarrow{E}) is the electric field vector. (\hat{n}) is the normal unit vector perpendicular to the surface. (dA) is the differential area of the surface.

Gauss’s law:

  • Gauss’s law states that the total electric flux through any closed surface is equal to the total charge enclosed by that surface. It is given by the equation: $$\oint\overrightarrow{E}\cdot\hat{n}dA=\frac{Q_{enc}}{\epsilon_0}$$ Where, $$\oint\overrightarrow{E}\cdot\hat{n}dA$$ represents the total electric flux through the closed surface. (Q_{enc}) is the total charge enclosed by the closed surface. (\epsilon_0) is permittivity of free space.

Applications of Gauss’s law:

Electric field of a uniformly charged sphere: For a uniformly charged sphere, the electric field at a distance (r) from the center of the sphere is given by:

  • Inside the sphere ((r<R)) $$\overrightarrow{E}=0$$

  • Outside the sphere ((r>R ))

$$\overrightarrow{E}=\frac{Q}{4\pi\epsilon_0 r^2}\hat{r}$$

Electric field of a uniformly charged infinite plane: For a uniformly charged infinite plane with surface charge density (\sigma), the electric field at a distance (d) from the plane is given by: $$\overrightarrow{E}=\frac{\sigma}{2\epsilon_0}\hat{n}$$ Where (\hat{n}) is the normal unit vector perpendicular to the plane.

Electric field of a charged conducting sphere: For a charged conducting sphere, the electric field at a distance (r) from the center of the sphere is given by:

  • Inside the sphere (r<R):

$$\overrightarrow{E}=0$$

  • Outside the sphere (r>R): $$\overrightarrow{E}=\frac{Q}{4\pi\epsilon r^2}\hat{r}$$


Table of Contents

sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें