Chemistry Problems
- structure_of_atom_ Question 76
- Chemical Bonding And Molecular Structure Vsepr Theory Question 38
- Redox Reactions Self Evaluation Test Redox Reactions Question 59
- The P-block Elements-i Boron Family Question 33
- Thermodynamics Topic Test Thermo Chemistry Thermodynamics Question 34
- Equilibrium Topic Test Chemical Equilibrium 6 5 21 Question 39
- Equilibrium Topic Test Ionic Equilibrium Question 34
- The S-block Elements Self Evaluation Test The S Block Elements Question 21
- Organic Chemistry Some Basic Principles & Techniques Self Evaluation Test Organic Chemistry Some Basic Principles Techniques Question 17
- Hydrocarbons Alkyne Question 105
- Solutions Topic Test Solutions Question 10
- Electrochemistry Self Evaluation Test Electrochemistry Question 100
- Chemical Kinetics Rate Law And Rate Constant Question 134
- The D-and F-block Elements Self Evaluation Test The D And F Block Elements Question 25
- Coordination Chemistry Numerical Value Type Questions Coordination Compounds Question 14
- Haloalkanes And Haloarenes Self Evaluation Test Haloalkanes And Haloarenes Question 11
- Alcohols Phenols And Ethers Properties Of Alcohol Phenol And Ethers Question 224
- Aldehydes Ketones Preparation Question 9
- Nitrogen Containing Compounds Introduction Of Nitrogen Containing Compounds Question 8
- Biomolecules Fats And Lipids Question 27
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- Ionic-Equillibrium-5-Problem-1
Solutions Topic Test Solutions Question 10
Question: Normal boiling point of water is 373 K (at 760 mm). Vapor pressure of water at 298 K is 23 mm. If the enthalpy of evaporation is 40.656 kJ/mol, the boiling point of water at 23 mm pressure will be:
Options:
A) 250 K
B) 294 K
C) 51.6 K
D) 12.5 K
Answer:
Correct Answer: B
Solution:
[b] Applying ClausiusClapeyron equation, we get $ \log \frac{P_2}{P_1}=\frac{\Delta H_{v}}{2.303R}[ \frac{T_2-T_1}{T_1\times T_2} ] $ $ \log \frac{760}{23}=\frac{40656}{2.303\times 8.314}[ \frac{373-T_1}{373T_2} ] $ This gives $ T_1 $ = 294.4 K.