Determinants & Matrices Question 1
Question: If $ p+q+r=0=a+b+c $ , then the value of the determinant is
Options:
A) 0
B) $ pa+qb+rc $
C) 1
D) none of these
Answer:
Correct Answer: A
Solution:
- [a] $ =pqr(a^{3}+b^{3}+c^{3}-3abc)- $ $ abc(p^{3}+q^{3}+r^{3}-3pqr) $ $ =pqr(a+b+c)(a^{2}+b^{2}+c^{2}-ab-bc-ca) $ $ -abc (p+q+r)(p^{2}+q^{2}+r^{2}-pq-qr-pr) $ = 0
BETA
