Atomic Physics Atomic Structure Question 130
Question: Four lowest energy levels of H-atom are shown in the figure. The number of possible emission lines would be [MP PMT 2001]
Options:
A) 3
B) 4
C) 5
D) 6
Answer:
Correct Answer: D
Solution:
Number of possible emission lines $ =\frac{n(n-1)}{2} $ Where n = 4; Number $ =\frac{4(4-1)}{2}=6. $
BETA
