thermodynamical_processes Question 83
Question: When 1 kg of ice at $ 0{}^\circ C $ melts to water at $ 0{}^\circ C, $ the resulting change in its entropy, taking latent heat of ice to be 80 cal/$ {}^\circ C $ , is
Options:
A) 273 cal/K
B) 253 cal/K
C) 263 cal/K
D) 293 cal/K
Answer:
Correct Answer: D
Solution:
[d] Change in entropy is given by $ dS=\frac{dQ}{T}\text{ or }\Delta S=\frac{\Delta Q}{T}=\frac{mL_{f}}{273} $ $ \Delta S=\frac{1000\times 80}{273}=293\text{ cal/K}\text{.} $
BETA
