A) $ -C\equiv N $
B) $ -S{O_3}H $
C) $ -COOH $
D) $ -N{O_2} $
સાચો જવાબ: D
આપેલ જૂથોની ડીએકિટિવ તકનીક નીચેના ક્રમમાં થાય છે
$ -NO _2>-SO _3H>-C\equiv N>-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}},-OH $
તેથી, ? $ NO _2 $ એ સૌથી વધુ ડીએકિટિવ જૂથ છે.
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