A) $ NO _2 $
B) $ NO_2^{-} $
C) $ NO_2^{+} $
D) $ NO_3^{-} $
सही उत्तर: C
प्रजाति संकरण बंध कोण
$ NO _2 $ $ sp $ $ {120^{{}^\circ }} $ से कम $ NO_2^{-} $ $ sp^{2} $ $ {{115.4}^{{}^\circ }} $ $ NO_2^{+} $ $ sp $ (रेखीय) $ {180^{{}^\circ }} $ $ NO_3^{-} $ $ sp^{2} $ $ {120^{{}^\circ }} $
इसलिए, $ NO_2^{+} $ में अधिकतम बंध कोण है,
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