A) $ \sqrt{6}h $
B) $ \sqrt{2}h $
C) $ 2\sqrt{3}h $
D) $ 0h $
सही उत्तर: A
d-कक्षक में इलेक्ट्रॉन का कोणीय संवेग $ =\sqrt{1+(1+1)}\frac{h}{2\pi } $ d-कक्षक के लिए,
$ I=2 $ $ =\sqrt{2(2+1)}\Rightarrow h=\sqrt{6}h $ $ ( \because h=\frac{h}{2\pi } ) $
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