A) B
B) Al
C) Ga
D) In
सही उत्तर: A
$ \because $ ‘B’ के संयोजी कोश में कोई रिक्त d-कक्षक नहीं होते,
इसलिए यह अपनी सहसंयोजकता को 4 से आगे नहीं बढ़ा सकता।
अर्थात् ‘B’ इस प्रकार का आयन
$ MF_6^{\text{3(-)}} $ अर्थात् $ BF_6^{3(-)} $ नहीं बना सकता।
इसलिए सही विकल्प [a] है।
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