A) t = 4.606/k
B) t = 2.303/k
C) t = 0.693/k
D) t = 6.909/k
सही उत्तर: A
रासायनिक गतिकी $ t=\frac{2.3}{K}\log \frac{a}{a-x} $
$ =\frac{2.3}{k}\log \frac{1.0}{1} $
$ \frac{2.303\times 2}{k} $
$ {t _{99}}=\frac{6.606}{k}4.606/k $
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