Atomic Structure Result Question 1-1
Among the following, the energy of $2 s$-orbital is highest in
(2019 Main, 12 April II)
(a) $\mathrm{K}$
(b) $\mathrm{H}$
(c) $\mathrm{Li}$
(d) $\mathrm{Na}$
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Answer:
Correct Answer: 1. ( a )
Solution:
The energy of $2 s$-orbital is lowest in $\mathrm{Rb}$ (rubidium). An orbital gets larger as the principal quantum number $n$ increases. Correspondingly, the energy of the electron in such an orbital becomes less negative, meaning that the electron is less strongly bound and has less energy. The graph of principal quantum number with atomic number is
BETA
