Atomic Structure Result Question 14
14. The energy of an electron in the first Bohr orbit of H-atom is $-13.6$ eV . The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)
(1988)
(a) $-3.4 $ eV
(b) $-4.2 $ eV
(c) $-6.8 $ eV
(d) $+6.8 $ eV
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Answer:
Correct Answer: 14. ( a )
Solution:
- Energy of electron in $H$-atom is determined by the expression:
$ E_n=-\dfrac{13.6}{n^2} \mathrm{eV} \quad \text { where, } n=1,2,3, \ldots . $
In excited states, $E_2=-\dfrac{13.6}{4}=-3.4 \mathrm{~eV}$
$ E_3=-\dfrac{13.6}{9}=-1.51 \mathrm{~eV} \text { etc. } $
BETA
