Atomic Structure Result Question 33
33. The correct set of quantum numbers for the unpaired electron of chlorine atom is
(1989, 1M)
$\quad\quad n \quad l \quad m$
(a) $2 \quad 1 \quad 0$
(b) $2 \quad 1 \quad 1$
(c) $3 \quad 1 \quad 1$
(d) $3 \quad 0 \quad 0$
Show Answer
Answer:
Correct Answer: 33. (c )
Solution:
- $\mathrm{Cl}(17)=1 s^2 2 s^2 2 p^6 3 s^2 3 p^5$
The last, unpaired electron has, $n=3, l=1(p)$ and $m$ can have any of the three value $(-1,0,+1)$.
BETA
