Atomic Structure - Result Question 51
27. For a $d$-electron, the orbital angular momentum is
$(1997,1 M)$
(a) $\sqrt{6}\left(\dfrac{h}{2 \pi}\right)$
(b) $\sqrt{2}\left(\dfrac{h}{2 \pi}\right)$
(c) $\left(\dfrac{h}{2 \pi}\right)$
(d) $2\left(\dfrac{h}{2 \pi}\right)$
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Answer:
Correct Answer: 27. (a)
Solution:
- The orbital angular momentum $(L)=\sqrt{l(l+1)} \dfrac{h}{2 \pi}$
$=\sqrt{6} \dfrac{h}{2 \pi}(l=2 \text { for } d \text {-orbital })$
BETA
