Atomic Structure - Result Question 62
38. The ratio of the energy of a photon of $200 $ Å wavelength radiation to that of $4000 $ Å radiation is
(1986,1 M)
(a) $\dfrac{1}{4}$
(b) 4
(c) $\dfrac{1}{2}$
(d) 2
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Answer:
Correct Answer: 38. (d)
Solution:
- $E=\dfrac{h c}{\lambda}$
$\Rightarrow \dfrac{E _1}{E _2}=\dfrac{\lambda _2}{\lambda _1}=2$
BETA
