Atomic Structure Result Question 80-1
80. Find out the number of waves made by a Bohr’s electron in one complete revolution in its 3rd orbit.
(1994, 3M)
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Solution:
- The Bohr de-Broglie relationship is
$ 2 \pi r=n \lambda=\text { circumference of Bohr’s orbit. } $
i.e. number of complete waves formed in one complete revolution of electron in any Bohr orbit is equal to orbit number, hence three.
BETA
