Chemical And Ionic Equilibrium
- Chemical And Ionic Equilibrium Result Question 1
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- Chemical and Ionic Equilibrium - Result Question 1
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- Chemical and Ionic Equilibrium - Result Question 8
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- Chemical And Ionic Equilibrium Result Question 43 — JEE PYQ Chapterwise
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- Chemical and Ionic Equilibrium - Result Question 9
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- Chemical And Ionic Equilibrium Result Question 48 — JEE PYQ Chapterwise
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- Chemical And Ionic Equilibrium Result Question 43 — JEE PYQ Chapterwise
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- Chemical and Ionic Equilibrium - Result Question 10
- Chemical And Ionic Equilibrium Result Question 51 — JEE PYQ Chapterwise
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- Chemical and Ionic Equilibrium - Result Question 55
- Chemical and Ionic Equilibrium - Result Question 56 — JEE PYQ Chapterwise
- Chemical and Ionic Equilibrium - Result Question 56 — JEE PYQ Chapterwise
- Chemical and Ionic Equilibrium - Result Question 56 — JEE PYQ Chapterwise
- Chemical and Ionic Equilibrium - Result Question 63-1
- Chemical and Ionic Equilibrium - Result Question 56 — JEE PYQ Chapterwise
- Chemical and Ionic Equilibrium - Result Question 56 — JEE PYQ Chapterwise
- Chemical and Ionic Equilibrium - Result Question 56 — JEE PYQ Chapterwise
- Chemical and Ionic Equilibrium - Result Question 56 — JEE PYQ Chapterwise
- Chemical and Ionic Equilibrium - Result Question 56 — JEE PYQ Chapterwise
- Chemical and Ionic Equilibrium - Result Question 56 — JEE PYQ Chapterwise
- Chemical and Ionic Equilibrium - Result Question 56 — JEE PYQ Chapterwise
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Chemical and Ionic Equilibrium - Result Question 19
19. At constant temperature, the equilibrium constant $\left(K _p\right)$ for the decomposition reaction, $N _2 O _4 \rightleftharpoons 2 NO _2$, is expressed by $K _p=\frac{4 x^{2} p}{\left(1-x^{2}\right)}$, where, $p=$ pressure, $x=$ extent of decomposition. Which one of the following statement is true?
(2001, 1M)
(a) $K _p$ increases with increase of $p$
(b) $K _p$ increases with increase of $x$
(c) $K _p$ increases with decrease of $x$
(d) $K _p$ remains constant with change in $p$ and $x$
Show Answer
Answer:
Correct Answer: 19. (d)
Solution:
- $\underset{1-x}{N _2 O _4} \rightleftharpoons \underset{2 x}{2 NO _2}, K _p=\frac{4 x^{2} p}{1-x^{2}} \cdot K _p$ is function of temperature only, does not change with either $p$ or $x$.





