Chemical and Ionic Equilibrium - Result Question 34

Answer:

Correct Answer: 34. (c, d)

Solution:

34. $NaNO _3(s) \rightleftharpoons NaNO _2(s)+\frac{1}{2} O _2(g), \Delta H>0$

$NaNO _3$ and $NaNO _2$ are in solid state, changing their amount has no effect on equilibrium. Increasing temperature will favour forward reaction due to endothermic nature of reaction. Also, increasing pressure will favour backward reaction in which some $O _2(g)$ will combine with $NaNO _2(s)$ forming $NaNO _3$.