Chemical and Ionic Equilibrium - Result Question 50

50. $N _2 O _4$ is $25 %$ dissociated at $37^{\circ} C$ and one atmosphere pressure. Calculate (i) $K _p$ and (ii) the percentage dissociation at $0.1$ $ atm$ and $37^{\circ} C$.

$(1988,4 M)$

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Solution:

<img src=“https://temp-public-img-folder.s3.amazonaws.com/sathee.prutor.images/sathee_image/snip_images_RxDOdR-ArbtOHKjkZxhZoyHVXfd-vWVUQ2ZOi-a5dTE_original_fullsize_png.jpg"width="340"/>

$ K_p=\dfrac{4 \alpha^2}{1-\alpha^2} p=\dfrac{4(0.25)^2}{1-(0.25)^2}=0.26 \mathrm{~atm} $

When $p=0.10 \mathrm{~atm}$

$ 0.26=\dfrac{4 \alpha^2(0.1)}{1-\alpha^2} \Rightarrow \alpha=0.46 $

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