Chemical Bonding - Result Question 1

1. The isoelectronic set of ions is

(2019 Main, 10 April I)

(a) $F^{-}, Li^{+}, Na^{+}$ and $Mg^{2+}$

(b) $N^{3-}, Li^{+}, Mg^{2+}$ and $O^{2-}$

(c) $Li^{+}, Na^{+}, O^{2-}$ and $F^{-}$

(d) $N^{3-}, O^{2-}, F^{-}$ and $Na^{+}$

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Answer:

Correct Answer: 1. (d)

Solution:

  1. Key Idea: Isoelectronic species contains same number of electrons.

The species with its atomic number and number of electrons are as follows :

Species (ions)At. no. $(\boldsymbol{Z})$No. of electrons
$N^{3-}$7$7+3=10$
$O^{2-}$8$8+2=10$
$F^{-}$9$9+1=10$
$Na^{+}$11$11-1=10$
$Li^{+}$3$3-1=2$
$Mg^{2+}$12$12-2=10$

Thus, option (d) contains isoelectronic set of ions.

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