Chemical Bonding Result Question 12

12. In which of the following pairs of molecules/ions both the species are not likely to exist?

(2013 Main)

(a) $\mathrm{H}_2^{+}, \mathrm{He}_2^{2-}$

(b) $\mathrm{H}_2^{-}, \mathrm{He}_2^{2-}$

(c) $\mathrm{H}_2^{2+}, \mathrm{He}_2$

(d) $\mathrm{H}_2^{-}, \mathrm{He}_2^{2+}$

Show Answer

Answer:

Correct Answer: 12. ( c )

Solution:

  1. Species having zero or negative bond order do not exist.

$\mathrm{H}_2^{2+}(1+1-2=0)=\sigma l s^0$

Bond order $=0$

$\mathrm{He}_2(2+2=4)=\sigma 1 s^2, \stackrel{*}{\sigma} 1 s^2$

$\text { Bond order }=\frac{N_b-N_a}{2}=\frac{2-2}{2}=0$

So, both $\mathrm{H}_2^{2+}$ and $\mathrm{He}_2$ do not exist.

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