Chemical Bonding - Result Question 90

66. The sum of the number of lone pairs of electrons on each central atom in the following species is

$\left[TeBr _6\right]^{2-},\left[BrF _2\right]^{+}, SNF _3$ and $\left[XeF _3\right]^{-}$

(Atomic numbers : $N=7, F=9, S=16, Br=35$, $Te=52, Xe=54)$

(2017 Adv.)

Show Answer

Answer:

Correct Answer: 66. $6$

Solution:


S.N.SpeciesNo. of $\sigma$ -bonds
with central atom		No. of L.P at
central atom
(i)$\operatorname{In}\left[TeBr _6\right]^{2-}$61
(ii)$\operatorname{In}\left[BrF _2\right]^{+}$22
(iii)In $SNF _3$40
(iv)$\operatorname{In}\left[XeF _3\right]^{-}$33
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