Chemical Kinetics - Result Question 13

14. Consider the given plots for a reaction obeying Arrhenius equation $\left(0^{\circ} C < T < 300^{\circ} C\right)$ : ( $k$ and $E _a$ are rate constant and activation energy, respectively)

(2019 Main, 10 Jan I)

<img src=“https://temp-public-img-folder.s3.amazonaws.com/sathee.prutor.images/sathee_image/cropped_2024_01_16_b4fdca9f34924034e8d8g-180_jpg_height_274_width_528_top_left_y_2297_top_left_x_389.jpg"width="450">

Choose the correct option.

(a) Both I and II are wrong

(b) Both I and II are correct

(c) I is wrong but II is right

(d) I is right but II is wrong

Show Answer

Answer:

Correct Answer: 14. (b)

Solution:

  1. The Arrhenius equation is,

$ k=A \cdot e^{-E _a / R T} $

where, $k=$ rate constant,

$ A=\text { Arrhenius constant }, E _a=\text { activation energy, } $

and $T=$ temperature in $K$

From the equation, it is clear that $k$ decreases exponentially with $E _a$. So, the plot-I is correct.

In the plot-II, $k$ is plotted with temperature (in ${ }^{\circ} C$ but not in $K$ ). So, at $0^{\circ} $ $C, k \neq 0$ and $k$ will increase exponentially with temperature upto $300^{\circ} $ $C$. Therefore, the plot-II is also correct.



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