Chemical Kinetics - Result Question 63
63. The rate constant for an isomerisation reaction, $A \rightarrow B$ is $4.5 \times 10^{-3}$ $ min$. If the initial concentration of $A$ is $1$ $ M$, calculate the rate of the reaction after $1 $ $h$.
(1999, 4M)
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Answer:
Correct Answer: 63. $(3.42 \times 10^{-3} $ $mol$ $ L^{-1} $ $min^{-1})$
Solution:
- $k t=\ln \frac{[A] _0}{[A]}$
$\Rightarrow 4.5 \times 10^{-3} \times 60 =\ln \frac{1}{[A]} \Rightarrow[A]=0.76$ $ M $
$\Rightarrow \text { Rate }=k[A] =4.5 \times 10^{-3} \times 0.76 $
$= 3.42 \times 10^{-3}$ $ mol $ $L^{-1}$ $ min^{-1}$
BETA
