Electrochemistry - Result Question 11
11.
$ \begin{aligned} \text { Given, } E_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^{\circ} & =-0.74 \mathrm{~V}, E_{\mathrm{MnO}4^{-} / \mathrm{Mn}^{2+}}^{\circ}=1.51 \mathrm{~V} \\ E{\mathrm{Cr}_2 \mathrm{O}7^{2-} / \mathrm{Cr}^{3+}}^{\circ} & =1.33 \mathrm{~V}, E{\mathrm{Cl} / \mathrm{Cl}^{-}}^{\circ}=1.36 \mathrm{~V} \end{aligned} $
Based on the data given above strongest oxidising agent will be
(2013 Main)
(a) Cl
(b) $\mathrm{Cr}^{3+}$
(c) $\mathrm{Mn}^{2+}$
(d) $\mathrm{MnO}_4^{-}$
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Answer:
Correct Answer: 11. (d)
Solution:
- Higher the standard reduction potential, better is oxidising agent. Among the given $E _{MnO _4^{-} / Mn^{2+}}^{\circ}$ is highest, hence $MnO _4^{-}$is the strongest oxidising agent.
BETA
