Electrochemistry Result Question 22
22. For the electrochemical cell, $\left(M \mid M^{+}\right) |\left(X^{-} \mid X\right)$,
$E^{\circ}\left(M^{+} / M\right)=0.44 \mathrm{~V}$ and $E^{\circ}\left(X / X^{-}\right)=0.33 \mathrm{~V}$.
From this data, one can deduce that
(2000, 1M)
(a) $M+X \longrightarrow M^{+}+X^{-}$ is the spontaneous reaction
(b) $M^{+}+X^{-} \longrightarrow MX$ is the spontaneous reaction
(c) $E_{\text {cell }}=0.77 \mathrm{V}$
(d) $E_{\text {cell }}=-0.77 \mathrm{V}$
Show Answer
Answer:
Correct Answer: 22. ( b )
Solution:
- The spontaneous cell reaction is
$X^{-}+M^{+} \longrightarrow M+X ; E^{\circ}=0.11 \mathrm{V}$
BETA
