Electrochemistry - Result Question 71

19. When a lead storage battery is discharged

(1986, 1M)

(a) $SO _2$ is evolved

(b) lead is formed

(c) lead sulfate is consumed

(d) sulphuric acid is consumed

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Answer:

Correct Answer: 19. $\left(300 cm^{2}\right)$

1. (a) 2. (c) 3. (b) 4. (c)
5. (d) 6. (a) 7. (a) 8. (b)
9. (b) 10. (c) 11. (c) 12. (a)
13. (c) 14. (a) 15. (d) 16. (a)
17. (d) 18. (d) 19. (b) 20. (b)
21. (b) 22. (b) 23. (c) 24. $(-14.16)$
25. (b) 26. (d) 27. (b) 28. (c)
29. (c) 30. (d) 31. (a) 32. (b)
33. (c) 34. (d) 35. (d) 37. $\left(10^{10}\right)$
38. $(0.05 M)$ 40. $\left(2.45 \times 10^{-12}\right)$ 41. $\left(5.89 \times 10^{7}\right)$
42. $\left(6.88 \times 10^{12}\right)$ 43. $(-0.222 V)$ 44. $(0.7926 V)$ 46. $\left(1.7 \times 10^{17}\right)$
47. $\left(1.57 \times 10^{-9}\right)$ 48. $\left(1.04 \times 10^{-14}\right)$ 49. $(8.6)$
52. $\left(6 \times 10^{2} S cm^{-1}\right.$ $\left.mol^{-1}\right)$ 53. $(4 mol)$

Solution:

  1. In a lead storage battery, sulphuric acid is consumed as :

$$ Pb+PbO _2+2 H _2 SO _4 \longrightarrow 2 PbSO _4+2 H _2 O $$



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